10p^2=64

Solution for 10p^2=64 equation:

10p^2=64

We move all terms to the left:

10p^2-(64)=0

a = 10; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·10·(-64)
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{10}}{2*10}=\frac{0-16\sqrt{10}}{20}
=-\frac{16\sqrt{10}}{20}
=-\frac{4\sqrt{10}}{5}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{10}}{2*10}=\frac{0+16\sqrt{10}}{20}
=\frac{16\sqrt{10}}{20}
=\frac{4\sqrt{10}}{5}
$